It is: (x+1)(x+12) when factored
x2 + 13x + 36 = (x + 9)(x + 4)
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
42 + x2 = 13x ∴ x2 - 13x + 42 = 0 ∴ (x - 6)(x - 7) = 0 ∴ x ∈ {6, 7}
vbh
11+2 = 13 and 2*11 = 22 So: x2+13x+22 = (x+2)(x+11) when factored
(x - 12)(x - 1)
x2 + 13x + 36 = 0 so (x+4)(x+9) = 0 so that x = -4 or x = -9
(x + 4)(x + 9)
(x-4)
x2 + 13x + 40 = x2 + 5x + 8x + 40 = x(x + 5) + 8(x + 5) = (x + 8)(x + 5)