3x3 + 192 3(x3 + 64) ========
If x2 and x3 are meant to represent x2 and x3, then x2 times x3 = x5 You find the product of exponent variables by adding the exponents.
x3 + 4x2 + 16x + 64 =x2*(x + 4) + 16(x + 4) = (x + 4)*(x2 + 16) which has no further real factors.
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
It is the commutative property of multiplication.
x3-343
(x + 7)(x2 - 7x + 49)
(x - 7)(x2 + 7x + 49)
64 is the cube of 4 so: x3 + 64 = (x + 4)(x2 - 4x + 16)
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
Subtract 1 from each side: x3 = 64; You might know that 4 cubed is 64, but if you don't then take log 64, divide it by 3 and take the antilog of your answer...
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
(x - 8)(x2 + 8x + 64)
(x - 4)(x^2 + 4x + 16)
71
x3 + 12x2 + 48x + 64= (x + 4)(x2 + 8x + 16)= (x + 4)(x + 4)(x + 4)= (x + 4)3
3x3 + 192 3(x3 + 64) ========