The browser used for posting questions on this site is rubbish. It is quite useless for mathematics since it strips out most symbols so that we cannot tell what the question is meant to be. We could try to guess but in some cases that is not possible and then we may as well make up our own questions and answer them!
(x+5)^2 and therefore x = -5
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
x(x - 1) = x2 + x x2 - x = x2 + x The only solution to this equation is x = 0
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6
-130
(x+5)^2 and therefore x = -5
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
If by "What is the answer to", you mean "How do you factor", then we can solve it as follows: x2 + 13xy + 36y2 = x2 + 4xy + 9xy + 36y2 = x(x + 4y) + 9y(x + 4y) = (x + 9y)(x + 4y)
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
x(x - 1) = x2 + x x2 - x = x2 + x The only solution to this equation is x = 0
x=4 x=0
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6
x2+16x-80 = 0 (x-4)(x+20) = 0 x = 4 or x = -20
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
x2+6x+9 = x+3 x2+6x-x+9-3 = 0 x2+5x+6 = 0 Solve by factoring or with the help of the quadratic equation formula: (x+3)(x+2) = 0 Therefore: x = -3 or x = -2