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Q: 12x-8 equals 10x plus 4

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2x + (10x - 4) = 20 2x + 10x - 4 = 20 12x - 4 = 20 12x = 24 x = 2

x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3

x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3

Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Solving the discriminant: k = -2

3x² + 10x = 8 : 3x² + 10x - 8 = 0 Solving for the roots of a quadratic equation gives : x = [-10 ± √(100 + 96)] ÷ 6 = [-10 ± √196] ÷ 6 = [-10 ± 14] ÷ 6 So x = 4/6 = 2/3 and x = -24/6 = -4 x = 2/3 and x = -4

Related questions

5x + 4 = 10x - 5 10x - 5x = 4 + 5 5x = 9 x = 1.8

y=-10x-4

x = 4

10x + 13 = 1710x = 17-1310x = 4x = 4/10x = 0.4

If: 4y+10x = 16Then: 4y = -10x+16And: y = -2.5x+4

6-3x = 5x-10x+2 4 = 8x-10x 4 = -2x x = -2

7x = 3 x = 3/7

2x + (10x - 4) = 20 2x + 10x - 4 = 20 12x - 4 = 20 12x = 24 x = 2

10x + 13 = 17 ie 10x = 17 - 13 so x = 4/10 = 0.4

3x-13x+4=0 -10x+4=0 4=10x 4/10=x simplified: x= 2/5

-4 = 17x so x = -4/17

12x - 6 = 10x +2 12x - 10x = 2 + 6 2x = 8 x = 4

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