3x2 - 10x - 8 = (3x + 2) (x - 4)
3x - 2y + 7x + 4y = 3x + 7x - 2y +4y = (3+7)x + (-2+4)y = 10x + 2y
3x+4=10 To solve: 3x+4=10 3x=6 x=2
X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
3x-4=5x+6 gives: 2x=-10 which gives x=-5
6-3x = 5x-10x+2 4 = 8x-10x 4 = -2x x = -2
3x-13x+4=0 -10x+4=0 4=10x 4/10=x simplified: x= 2/5
6-3x = 5x-10x+10 6-3x = -5x+10 -3x+5x = 10-6 2x = 4 x = 2
x -3x + 4 = 3 - 9-2x + 4 = -6-2x = -102x = 10x = 5
68-3x=10x+16 Combine like terms. (Subtract 16 from both sides. Subtract -3x from both sides.) This will give you: 52=13x Divide both sides by 13. Your answer is x=4.
(-3x + 4)(x - 2)
3x2 - 10x - 8 = (3x + 2) (x - 4)
3x2 + 10x - 8 = 0 3x2 + 12x - 2x - 8 = 0 3x(x + 4) - 2(x + 4) = 0 (3x - 2)(x + 4) = 0 So 3x - 2 = 0 or x + 4 = 0 so x = 2/3 or x = -4
4x-y=2, thereforey=4x-2sub y into 3x+2y=6...3x+8x-4=611x=10x=10/11
3x² + 10x = 8 : 3x² + 10x - 8 = 0 Solving for the roots of a quadratic equation gives : x = [-10 ± √(100 + 96)] ÷ 6 = [-10 ± √196] ÷ 6 = [-10 ± 14] ÷ 6 So x = 4/6 = 2/3 and x = -24/6 = -4 x = 2/3 and x = -4
They intersect at the point of: (-3/2, 11/4)
7x+3=10x-9(shift +3 & 10x) 7x-10x=-9-3(signs changed) -3x=-12(divide both sides by -3) x=4