Any number that is divisible by 3 has the sum of its digits equal to 3 or a multiple of 3.
387436 . . . 3 + 8 + 7 + 4 + 3 + 6 = 31 which is NOT a multiple of 3.
2345 . . . . .2 + 3 + 4 + 5 = 14 which is also NOT a multiple of 3.
If we make the first number 387435 then this is divisible by 3.
And if we alter the second number to 2346 then this now is divisible by 3.
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The digital root of a nuber is the sum of all its digits.
The digital root of 387436 = the digital root of 31 = 4. Since 4 is not divisible by 3, 387436 is not divisible by 3.The digital root of 2345 = the digital root of 14 = 5. Since 5 is not divisible by 3, 2345 is not divisible by 3, either.,
To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.
2,4,6,8,and 0 are divisible by 2 in the ones digit. Zero is only divisible in a number with 2 digits or more. 0 itself is not divisible by 2.
13795. If the ones digit is even; 2,4,6,8,0, then it is divisible by 2.This is No. Five is not even.
No; for a number to be divisible by 10, the last number (ones place) must be zero.
No. In order for a number to be divisible by 10, the ones digit must be zero (0).