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47 is divided by a mystery number There is a remainder of 3 What could the mystery number be?
Well, isn't that just a happy little math problem! If you have 47 apples and you divide them by a mystery number, and there's a remainder of 3, it means the mystery number could be 2, 4, 6, or any number that leaves a remainder of 3 when dividing 47. Just remember, there are many possibilities and each one is like a unique brushstroke on the canvas of numbers.
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How to work out 47 is divided by a mystery number there is a remainder of 3 what could the mystery number be-?
44
How to work out 47 is divided by a mystery number there is a remainder of 3 what could the mystery number be?
15.6667
What number divided by 3 has a remainder of 2 and divided by five has a remainder of three?
x = 2 mod 3; x = 3 mod 5. Equivalently, x = 3m + 2 = 5n + 3. One such number is 23; others could be found.
What is the largest remainder possible if a number is divided by 9?
The largest remainder would be 8, because if it were 9 you could divide the number once more. The largest remainder you can have is always one less than what you're dividing by. So if you're dividing by 10, your largest remainder is 9. If you're dividing by 100, it's 99. And so on.
What 2 numbers don't belong 67 72 82 95 77 53 97 and 87?
This is an extremely poor question. There are 28 pairs of numbers and, in less than 10 minutes, I could find reasons why 17 pair were different from the other numbers in the set. A bit more time and I am sure I could do the rest. So here they are: 53 and 72: leave a remainder of 15 when divided by 19. 53 and 77: leave a remainder of 5 when divided by 12. 53 and 82: leave a remainder of 24 when divided by 29. 53 and 87: leave a remainder of 2 when divided by 17. 53 and 95: leave a remainder of 11 when divided by 21. 53 and 97: leave a remainder of 9 when divided by 11. 67 and 95: leave a remainder of 11 when divided by 28. 67 and 87: leave a remainder of 7 when divided by 17. 67 and 97: leave a remainder of 7 when divided by 30. 72 and 82: leave a remainder of 0 when divided by 2 (are even). 72 and 87: leave a remainder of 0 when divided by 3 (multiples of 3). 72 and 95: leave a remainder of 3 when divided by 23. 72 and 97: leave a remainder of 22 when divided by 25. 77 and 95: leave a remainder of 5 when divided by 9. 77 and 97: leave a remainder of 17 when divided by 20. 82 and 95: leave a remainder of 4 when divided by 13. 87 and 95: leave a remainder of 7 when divided by 8.
How to work out 47 is divided by a mystery number there is a remainder of 3 what could the mystery number be-?
44
How to work out 47 is divided by a mystery number there is a remainder of 3 what could the mystery number be?
15.6667
What can be the largest possible remainder if the divisor in a given division problem is 48?
The remainder is the number that is left over after the initial value has been divided as much as it can. If any numbers greater than 48 were present as a remainder, then these could be divided further into 48. If 48 is present as the remainder, then this can be divided by 48 to give 1, leaving no remainder. Thus, the largest possible remainder if the divisor is 48 is 47.
What number divided by 3 has a remainder of 2 and divided by five has a remainder of three?
x = 2 mod 3; x = 3 mod 5. Equivalently, x = 3m + 2 = 5n + 3. One such number is 23; others could be found.
What is the largest remainder possible if a number is divided by 9?
The largest remainder would be 8, because if it were 9 you could divide the number once more. The largest remainder you can have is always one less than what you're dividing by. So if you're dividing by 10, your largest remainder is 9. If you're dividing by 100, it's 99. And so on.
Which number could be a reminder for a problem with a divisor of 8?
Any non-negative number less than 8. If the number being divided is not a whole number, the remainder will not be a whole number either.
What 2 numbers don't belong 67 72 82 95 77 53 97 and 87?
This is an extremely poor question. There are 28 pairs of numbers and, in less than 10 minutes, I could find reasons why 17 pair were different from the other numbers in the set. A bit more time and I am sure I could do the rest. So here they are: 53 and 72: leave a remainder of 15 when divided by 19. 53 and 77: leave a remainder of 5 when divided by 12. 53 and 82: leave a remainder of 24 when divided by 29. 53 and 87: leave a remainder of 2 when divided by 17. 53 and 95: leave a remainder of 11 when divided by 21. 53 and 97: leave a remainder of 9 when divided by 11. 67 and 95: leave a remainder of 11 when divided by 28. 67 and 87: leave a remainder of 7 when divided by 17. 67 and 97: leave a remainder of 7 when divided by 30. 72 and 82: leave a remainder of 0 when divided by 2 (are even). 72 and 87: leave a remainder of 0 when divided by 3 (multiples of 3). 72 and 95: leave a remainder of 3 when divided by 23. 72 and 97: leave a remainder of 22 when divided by 25. 77 and 95: leave a remainder of 5 when divided by 9. 77 and 97: leave a remainder of 17 when divided by 20. 82 and 95: leave a remainder of 4 when divided by 13. 87 and 95: leave a remainder of 7 when divided by 8.
What is 608 divided by 3?
202.6667
What number could be a remainder when dividing by 4?
5
The number when divided by 3 and 7 leaves a remainder 2?
Let the number be represented by x. When x is divided by 3, the remainder is 2, which can be expressed as x ≡ 2 (mod 3). Similarly, when x is divided by 7, the remainder is also 2, which can be written as x ≡ 2 (mod 7). To find the number that satisfies both conditions, we can use the Chinese Remainder Theorem to find the smallest positive integer that satisfies both congruences, which in this case would be 23.
What is the answer to 81 over 3 as a mixed number?
Usually, to find a mixed number answer, you divide 81 (in this case) by 3, and write the answer as the integer part of the mixed number, and the remainder over 3 as the fractional part of the mixed number. However, since 81 divided by 3 is 27, with no remainder, there is no reason to write it as a mixed number. It could be written as 27 and 0/3, but this is not generally the accepted way to write an answer to a division problem that does not involve a remainder.
Could 34 go into 48?
Not evenly, 48 divided by 34 equals 1 with a remainder of 14.
