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Earn +20 ptsQ: 8x plus y -16
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The equation of tangent to curve y x 2 at 4 16 is 8x plus y plus 16 0 8x-y-16 0 8x-y plus 16 0 8x plus y-16 0 B is right answer how?
There is not a way to give the answer to this equation. You will have to give me the value of the letters.
If 8x plus 4y equals 16 what is the slope?
If 8x + 4y = 16, then y = - 2x + 4 Thus the slope is -2 and the intercept is 4.
What is y equals x2-8x plus 3 in vertex form?
x^2-8x+3 = x^2-8x+16-16+3 = (x-4)^2-13 y=(x-4)^2 -13 The vertex is (4,-13).
How to solve by using elimination methood 8x plus y 16 plus 3x plus y 5?
The given expression can't be solved as equations because there are no equality signs.
What is 8x plus y plus 6 - 7?
12
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