By elimination: x = 3 and y = 0
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals". Unfortunately, what you might have considered a pair of simultaneous equation, is being displayed to us as one expression!
You cannot solve one linear equation in two variables. You need two equations that are independent.
(2,-2)
Yes and it works out that x = 3 and y = 4
By elimination: x = 3 and y = 0
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals". Unfortunately, what you might have considered a pair of simultaneous equation, is being displayed to us as one expression!
You cannot solve one linear equation in two variables. You need two equations that are independent.
(2,-2)
Yes and it works out that x = 3 and y = 4
With great difficulty because without any equality sign the given terms can't be considered to be an equation.
No. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
y=16 x= -4
The answer is that it cannot be done. To solve a set of equations in k variables (in this case, 2) you need at least two independent equations.
16
Using the elimination method, 3x + (2y) times 18x - 3y - 5 gives the result of 36xy + 3x - 3y - 5.