x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
The answer is A.
9 + x = 0 x = -9 Hence 9 - 9 = 0
9 x 1012 = 9,000,000,000,000 = (9 x 1012) + (0 x 1011) + (0 x 1010) + (0 x 109) + (0 x 108) + (0 x 107) + (0 x 106) + (0 x 105) + (0 x 104) + (0 x 103) + (0 x 102) + (0 x 101) + (0 x 100).
^^^WRONG. change the low E string to a D (drop D tuning), the chords are: 0-------high E string 0 9 9 7 x-------low E string (now a D) 0 0 6 6 4 x 0 0 x 7 7 7 0 0 x 9 9 9 the chorus: 0 0 9 9 7 x 0 0 x 9 9 9 0 0 x 6 6 6 0 0 x 7 7 7 hope this helps :)
x2 + 14x + 45 = 0 => x2 + 9x + 5x + 45 = 0 => x(x + 9) + 5(x + 9) = 0 (x + 9)(x + 5) = 0 so that x = -5 or x = -9
(3 x 100000000) + (0 x 10000000) + (9 x 1000000) + (0 x 100000) + (9 x 10000) + (9 x 1000) + (9 x 100) + (9 x 10) + (0 x 1)
y=x+9 y'=1 x+9=0 x=-9 y=-9+9 y=0
(0 x 69) 9
Zero because 0 times 9 = 0
x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.