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A regulation doubles tennis court has an area of 2808 square feet. If it is 6 feet longer than twice its width determine the dimensions of the court.?
Wiki User
∙ 7y ago
Use the equation for the area of a rectangle:A = lw (area = length x width)
Call the width "w", then the length will be "w+6". In the previous equation, replace the letters you know - in this case, all of them - and you get:
2808 = w(w+6)
Solve this equation. Since you have a quadratic equation, you'll get two solutions; one will have negative numbers, so you keep only the solution where "w" is positive.
Wiki User
∙ 7y ago
Wiki User
∙ 7y agoThe dimensions work out as 78 feet by 36 feet
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