I think the trading is the other way around and then the answer is 18 marbles in all.
18 of them.
The theoretical probability of randomly drawing a green marble can be calculated by dividing the number of green marbles by the total number of marbles in the bag. In this case, there are 12 green marbles out of a total of 5 red marbles + 8 blue marbles + 12 green marbles, which is 25 marbles in total. Therefore, the theoretical probability of drawing a green marble is 12/25 or 48%.
There is a one in 2 chance of getting a green marble.
sure chance
The probability of picking a green marble from a box that only contains blue marbles is zero.
if you pick one marble at random, the odds are 17/(42+17+27) or 17/86 or about 20%
You would be more likely to pull out a white marble as there are no red marbles in the bag.
It is 2/10.
The probability of drawing a white marble is .46
If you pick only one marble from the bag, at random, it can be any one of 26 marbles. Out of these, 5 of the marbles are green. Thus, there are 26 possible outcomes out of which 5 are favourable - to the event that the marble is green. Therefore the probability of a green marble is 5/26. The calculations become more complicated if you consider choosing a green marble in several attempt: it depends on whether or not the marbles are replaced before the next one is picked.
1 in 52
0No blue marbles in the bag.