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A bag has 13 green marbles What is the probability pf drawing out a green marble?
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
What is the probability of 3 green marbles?
the probability is you'd get a green marble any other color is impossible. So, the probability is certain
What is the probability of choosing a marble that is not blue out of 5 red and 6 green?
100%
A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
What is the probability of choosing a red marble from a jar 5 red 6 green and 4 blue marble?
1/3 or 33%
A bag has 13 green marbles What is the probability pf drawing out a green marble?
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
What is the probability of 3 green marbles?
the probability is you'd get a green marble any other color is impossible. So, the probability is certain
What is the probability of choosing blue marble followed by a green marble from a bag containing 5 blue 5 green and 5 red marbles?
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
There are 4 bags each containing 4 red marbles and 1 green marble If you grab one marble from each bag what is the probability of grabbing at least 2 green marbles?
Let's consider first one bag: The probability to grab one green marble is Pg=1/5 The probability to grab one red marble is Pr=1-Pg=4/5 For the 4 bags, it's a binomial distribution: probability to get k green out of n bags, P(X=k)=nCk pk (1-p)n-k = nCk Pgk Prn-k Now, the probability to grab at least 2 green marbles from 4 bags is 1 - (Probability to get no green marble from 4 bags) - (Probability to get just one green marble from 4 bags) Probability to get no green marble is = 4C0 (4/5)4 = (4/5)4 (n=4, k=0, no green marble from each bag, 4C0 Pr4) Probability to get just one green marble is = 4C1 (1/5) (4/5)3 (n=4, k=1, one green marble from one bag and red marbles from the other ones, 4C1 Pg Pr3) Probability to grab at least 2 green marbles from 4 bags is 1-(4/5)4-4*(1/5)(4/5)3 = 0.1801
What is the probability of choosing a marble that is not blue out of 5 red and 6 green?
100%
What is the probability of getting green if there is 3 blue 2red and 4 green?
If there is 3 blue 2 red and 4 green. What is the probability of getting green?
If a bag contains 3 green marbles 5 blue marbles and 2 yellow marbles find the probability that the marble is blue?
Assuming that you're only taking out one marble, then:Your sample space --> 3 + 5 + 2 = 10The probability of getting a blue marble on the first draw is 3/10 or 0.3
What is the probability of not choosing a green marble from a jar containing 5 red 6 green and 4 blue marbles?
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
What is the probability of choosing a green marble from A jar containing 4 red 6 green and 5 blue marbles?
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
What is the probability of choosing a red marble from a jar 5 red 6 green and 4 blue marble?
1/3 or 33%
What is the theoretical probability of randomly drawing a green marble if there are 5 red marbles 8 blue marbles and 12 green marbles in a bag.?
The theoretical probability of randomly drawing a green marble can be calculated by dividing the number of green marbles by the total number of marbles in the bag. In this case, there are 12 green marbles out of a total of 5 red marbles + 8 blue marbles + 12 green marbles, which is 25 marbles in total. Therefore, the theoretical probability of drawing a green marble is 12/25 or 48%.
