8
v = u + at = 0 + 2*10 = 20 metres per second.
instantaneous acceleration* * * * *No it does not.The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.
To be able to calculate a mi to the second power you need to
3 / 12 = 0.25 miles/second2.
6 meters per second. Explanation: After 1 second = 2 meters per second. After 2 seconds = 4 meters per second. After 3 seconds = 6 meters per second.
If the acceleration was constant (15 + 25) /2 = 20 (time does not figure into the averaging at all!)
If the displacement of the object (its position) can be described as a functional or algebric equation, you can find the instant speed of this object by calculating the derivative of its displacement equation, knowing that speed is the first derivative of position and acceleration, its second.
Approx 5.1 metres.
a falling object accelerates 32ft per second per second
19.614 meters/second is.
The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).
velocity is just a general term for speed (it could be average velocity or instantaneous velocity). Instantaneous velocity/speed (same thing) is the speed at that second. If you are familiar with calculus, it is the derivative of the position graph. Whereas average velocity is how fast the object is going in, for example, 1 hour, it is the speed that is maintained the whole hour (or the average) Instantaneous would be that at the second, at for example t=1.425, the speed is 24m/h . something along those lines
Increasing it's velocity.In the math sense, It is the second derivative.
If an object accelerates, there must be a force acting on it according to newton's second law, so I would answer true.
If an object accelerates, there must be a force acting on it according to newton's second law, so I would answer true.
gravity
The second car accelerates
instantaneous acceleration* * * * *No it does not.The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.