8
instantaneous acceleration* * * * *No it does not.The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.
To be able to calculate a mi to the second power you need to
3 / 12 = 0.25 miles/second2.
6 meters per second. Explanation: After 1 second = 2 meters per second. After 2 seconds = 4 meters per second. After 3 seconds = 6 meters per second.
If the acceleration was constant (15 + 25) /2 = 20 (time does not figure into the averaging at all!)
If the displacement of the object (its position) can be described as a functional or algebric equation, you can find the instant speed of this object by calculating the derivative of its displacement equation, knowing that speed is the first derivative of position and acceleration, its second.
When a body accelerates, its velocity changes, leading to a change in position over time. This acceleration is a result of the application of a force on the body, as described by Newton's second law (F=ma). Essentially, the body's motion is affected by the net force acting on it.
The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).
Instantaneous energy can be measured by calculating the power of a system at a specific moment. This can be done by measuring the rate of energy transfer or by using a power meter. The unit of measurement for instantaneous energy is typically in watts or joules per second.
Increasing it's velocity.In the math sense, It is the second derivative.
If an object accelerates, there must be a force acting on it according to newton's second law, so I would answer true.
gravity
The second car accelerates
Its almost instantaneous. In micro seconds...or at the max. second.
instantaneous acceleration* * * * *No it does not.The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.
5 metres per second squared
That's easy, if the car is initially traveling at 25 meters per second and gradually accelerates 3 meters per second for 6 seconds then the car is traveling at 43 meters per second.