y = 2x + 1.
Y=mx+b
The equation for a line of slope m going through point (Xo, Yo) is given by: y - Yo = m(x - Xo) So for line of slope 2 going through (1, 9) the equation is: y - 9 = 2(x - 1) ⇒ y = 2x + 7
The standard form is: 5x - y + 4 = 0
Point: (1, 4) Slope: -3 Equation: y = -3x+7
y = 2x + 1.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
sda
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
write an equation that has a slope 7 and passes through the point (2,17)
Y=2x+6
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
(0,-6) m=-2