To find the slope-intercept form of the equation of a line that goes through the point (2, 2) and is parallel to the line ( y = x + 7 ), we first identify the slope of the given line, which is 1. Since parallel lines have the same slope, the new line will also have a slope of 1. Using the point-slope form ( y - y_1 = m(x - x_1) ) with ( m = 1 ) and the point (2, 2), we can rewrite it as ( y - 2 = 1(x - 2) ), which simplifies to ( y = x ).
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Any equation with the form y=c is parallel to the y-axis, where c is a constant.
The given expression is not an equation because it has no equality sign but for a line to be parallel to another line they both will have the same slope but with different y intercepts
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
y = 2x + 1.
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
i dont knows
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
The equation is x = -7.
The equation in slope-intercept form would be y=-2x
Known equation: 3x+5y = 6 or y = -3/5x +6/5 Slope of equation: -3/5 Slope of parallel equation: -3/5 Parallel equation: y-1 = -3/5(x-3) => 5y = -3x+14 Parallel equation in its general form: 3x+5y-14 = 0
The parallel equation works out as: 4y = 3x+1 which can be expressed in the form of 3x-4y+1 = 0
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Any equation with the form y=c is parallel to the y-axis, where c is a constant.
If you mean: 9x+3y = 6 then y = -3x+2 and its parallel equation is y = -3x-5
If you mean: y=-5x+10 and the point (3, 10) then the parallel equation is y=-5x+25