زتلرش
A value of the variable that makes the equation statement true is called a solution. For example, in the equation ( x + 2 = 5 ), the value ( x = 3 ) is a solution because substituting it into the equation yields a true statement. There can be multiple solutions or none, depending on the equation. To find a solution, you can isolate the variable and solve for its value.
y' = e^{y - x}, y(0) = 0 y = \square
The value of the variable that makes an equation true is known as the solution to the equation. It is the number that, when substituted for the variable, satisfies the equation's conditions. To find this value, one typically manipulates the equation using algebraic techniques until the variable is isolated on one side. The resulting value can then be verified by substituting it back into the original equation.
when you find the value, you SOLVED the equation. you CHECK the equation when you substitute the value in the variables place and check that the equation is true.
The result of solving an equation to find values for the variables is known as the solution set. This set includes all possible values that satisfy the equation, making it true when substituted back into the original equation. If there is a unique solution, it is a single value; if there are multiple solutions, they are typically expressed in a set or as a range. In some cases, there may be no solution at all.
The solution
Replace a value for x, then solve for y, to find the corresponding value for y. Repeat for other values of x.
You haven't given the solution to the equation ! 3x + 20 = ? If you have the number for the question-mark - you can find the value of x ! For example in the equation 3x + 20 = 50... the value of x is 10.
It depends on the equation.
To find ln 2.33, you need a calculator. It is the solution of the equation e^x = 2.33. ln 2.33 = 0.84586 (using a calculator)
To find the value of ( y ) when ( x = 11 ), we can substitute ( x ) with 11 in the equation ( 7x - 9y = 23 ) and solve for ( y ): [ 7(11) - 9y = 23 ] [ 77 - 9y = 23 ] [ -9y = 23 - 77 ] [ -9y = -54 ] [ y = \frac{-54}{-9} ] [ y = 6 ] So, when ( x = 11 ), ( y = 6 ).
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.