No.
If the equations or inequalities have the same slope, they have no solution or infinite solutions. If the equations/inequalities have different slopes, the system has only one solution.
When there is an ordered pair that satisfies both inequalities.
It is a point that may or may not be a solution to the system - depending on whether or not the inequalities are strict.
yes it is possible for a system of two linear inequalities to have a single point as a solution.
It depends on whether the inequalities are strict or not.
Which system of inequalities has no solution?A.y > 3x - 1y < 3x - 3B.y > 3x + 3y < 3x + 7C.y > -1y < 2y > 2x - 3re...
An inequality determines a region of space in which the solutions for that particular inequality. For a system of inequalities, these regions may overlap. The solution set is any point in the overlap. If the regions do not overlap then there is no solution to the system.
yes
Yes, you can say something like y < infinity and y > -infinity .
The solution to a system of inequalities is where the solutions to each of the individual inequalities intersect. When given a set of graphs look for the one which most closely represents the intersection, this one will contain the most of the solution to the the system but the least extra.
Systems of inequalities in n variables with create an n-dimensional shape in n-dimensional space which is called the feasible region. Any point inside this region will be a solution to the system of inequalities; any point outside it will not. If all the inequalities are linear then the shape will be a convex polyhedron in n-space. If any are non-linear inequalities then the solution-space will be a complicated shape. As with a system of equations, with continuous variables, there need not be any solution but there can be one or infinitely many.