In case you meant 64x^3 - 27y^3, that factors to (4x - 3y)(16x^2 + 12xy + 9y^2)
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(5x - 2)(x - 5)
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
You try to find two factors of -58 whose sum is -27 .You find that -29 and +2 will do it, so . . .x2 - 27x - 58 = (x - 29) (x + 2)
3x2 + 27x +60
9xy(3xy - 4)