(5x - 2)(x - 5)
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
You try to find two factors of -58 whose sum is -27 .You find that -29 and +2 will do it, so . . .x2 - 27x - 58 = (x - 29) (x + 2)
3x2 + 27x +60
9xy(3xy - 4)
-x^6(64x^3 - 27)
(5x - 2)(x - 5)
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
You try to find two factors of -58 whose sum is -27 .You find that -29 and +2 will do it, so . . .x2 - 27x - 58 = (x - 29) (x + 2)
20x2 - 27x -8 20 * -8 is -160, and -32 and 5 add to -27 20x2 - 32x + 5x - 8 4x(5x-8) + 1(5x-8) (4x + 1)(5x-8)
3x2 + 27x +60
27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3
27x + 3 use distibutive law to factor
0
5x2 - 27x - 18 = (5x + 3)(x - 6)
cube root of 27 = 3, so 3^12 = 531 441 * * * * * If the question is about 27x, rather than 27, the answer is as follows: cuberoot(27x12) = (27x)12/3 = (27x)4 = 531441x4
(2x - 3)(x - 12)