(a + 2 - b) (a + 2 + b)
4(x+y)^2
(b + 4)(b + 4)
(3x - y+ 2)(3x + y + 2)
(3+2) (4+48)
c2 - 6cd + 9d2 - 4 The first three terms are a complete square = (c - 3d)2 - 4 Difference of two squares = (c - 3d + 2)(c - 3d - 2)
(a + 2 - b) (a + 2 + b)
4(x+y)^2
Oh, dude, you're hitting me with some math now? Alright, so you're looking at the quadratic expression x^2 + 5x + 4. To factor this, you want to find two numbers that multiply to 4 (the constant term) and add up to 5 (the coefficient of the x term). Those numbers are 1 and 4, so the factored form is (x + 1)(x + 4). That's it, easy peasy lemon squeezy!
(b + 4)(b + 4)
Factor it out: (x+2) squared
(3x - y+ 2)(3x + y + 2)
(2x+3)(2x+4)
(3+2) (4+48)
(b + 8)(b + 4)
2(x^2 + 2)
(x-1)(x-4)