2(x^2 + 2)
(2x+3)(2x+4)
4
Factor it out: (x+2) squared
(2x-4)(x-1) = 0
It is (2x-5)(x-4) when factored
2(x + 4)(x + 2)
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
(x+2)(x+2) or (x+2)^2
Assuming it's a plus sign, that factors to (2x + 1)(x + 4)
6x^2 + 11x + 4 is a Quadratic Statement. It is NOT an equation, because there is no 'equals' (=). It will factor to ( 3x + 4)(2x + 1)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
2(x - 2)(x - 4)