14
I can find 13 ways, not just 7, to make 60 from adding numbers in the 4, 5 and 9 times tables.
23,3 19,7 13,13
Not counting negative numbers (which would give you an infinite number of ways of adding numbers together to equal 10), there are 6 different ways (permutations) of adding numbers together to equal 10. 0 + 10 1 + 9 2 + 8 3 + 7 4 + 6 5 + 5
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Greatest common factor (GCM) is the largest number that divides into 2 or more numbers. For example: The GCM for 12 and 18 is 6. There are many ways to find the GCM. Here are ways you can find the GCM:Inverted DivisionList out all the factors of both of the numbers
To find how many ways to make 12 with three single-digit numbers (from 0 to 9), we can consider combinations of numbers that add up to 12. The valid combinations include repetitions of numbers, such as (3, 4, 5) and (2, 5, 5). However, since the order of addition matters, each unique combination can be arranged in multiple ways, which increases the total count. A systematic approach or generating functions can be used to enumerate all valid combinations and permutations, leading to a total of 29 distinct combinations.
We can't answer that unless you tell us what two ways were shown.
Write 2 ways in which whole numbers and decimal numbers are different
Adding more solute or adding more solvent
To find how many integers from 1 to 1000 have none of their digits repeated, we can analyze the problem by considering the number of digits in the integers. For 1-digit numbers (1-9), there are 9 options. For 2-digit numbers (10-99), the first digit can be chosen in 9 ways (1-9), and the second digit in 9 ways (0-9 excluding the first digit), giving 9 × 9 = 81 combinations. For 3-digit numbers (100-999), the first digit can be chosen in 9 ways, the second in 9 ways, and the third in 8 ways, resulting in 9 × 9 × 8 = 648 combinations. Adding these, we find the total: 9 + 81 + 648 = 738 integers with non-repeating digits from 1 to 1000.