y = f(x) = 2x2 - 3x + 10dy = (4x - 3) dxNote:It's possible that the function in the question may have been f(x) = (2x)2 - 3x + 10 .If that's the case, thendy = (8x - 3) dx
Given a value of x, find the value for -3x + 2
Yes.
-3/2
-4. x=2
5
5
-2
y = f(x) = 2x2 - 3x + 10dy = (4x - 3) dxNote:It's possible that the function in the question may have been f(x) = (2x)2 - 3x + 10 .If that's the case, thendy = (8x - 3) dx
Given a value of x, find the value for -3x + 2
Yes.
y = 2 sin 3x y' = 2(sin 3x)'(3x)' y' = 2(cos 3x)(3) y' = 6 cos 3x
y=2 sin(3x) dy/dx = 2 cos(3x) (3) dy/dx = 6 cos(3x)
x is 30 to work it out- 3x 30=90 90-2=88
-3/2
-4. x=2
3x + 2 = 3x + 6 This is not possible.