-29
Every number from 1-30... 1,2,3,4,5,6,7,8,9,10,11,12,1,3,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,and 30.
9, 10, 11. Let the middle number be n, then the three numbers are (n-1), n, (n+1) with: (n-1) + n + (n+1) = 30 → 3n = 30 → n = 10 → the numbers are 10-1 = 9, 10 and 10+1 = 11.
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30
1. Yi
(5x5)+(4+1)=30 :)
The factors of all the numbers 1 through 30 include all the numbers 1 through 30.
The two perfect numbers between 1 and 30 are: 6, 28
The sum of whole numbers 1 through 30 is 465.
that is not even close to a question 6 occures in first 30 numbers for just 1 time so probabability of 6 in 30 numbers= 1/30
(30 + 1) * 30/2 ie 465
Of the numbers from 1 to 30, only 30 has all three of those numbers as factors.
Every number from 1-30... 1,2,3,4,5,6,7,8,9,10,11,12,1,3,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,and 30.
The two numbers are 6 and -5. 6 x (-5) = -30, 6 + (-5) = 1.
1 and 3. These are the only whole numbers to go into both 27 and 30.
9, 10, 11. Let the middle number be n, then the three numbers are (n-1), n, (n+1) with: (n-1) + n + (n+1) = 30 → 3n = 30 → n = 10 → the numbers are 10-1 = 9, 10 and 10+1 = 11.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
the answer was nothing