molly-tyga
ΔRST is dilated about the origin, O, to create ΔR'S'T'. Point R is located at (3, 9), and point R' is located at (1.2, 3.6). Which scale factor was used to perform the dilation?
dilation
If the original point was (-4, 12) then the image is (-16, 48).
If you have the coordinates, you can do calculations. You can get the distance with the Pythagorean formula; the x-point of the midpoint is the average of both x-coordinates, similar for the y-point.
The solution is the coordinates of the point where the graphs of the equations intersect.
A point has coordinates (-3, 0). Where is it located in the coordinate plan?A point has coordinates (-3, 0). Where is it located in the coordinate plan?
Well this is my thought depending on where the point of dilation is the coordinates of the give plane is determined. The point of dilation not only is main factor that positions the coordinates, but the scale factor has a huge impact on the placement of the coordinates.
The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.
dilation
The coordinates of a point are in reference to the origin, the point with coordinates (0,0). The existence (or otherwise) of an angle are irrelevant.
If the original point was (-4, 12) then the image is (-16, 48).
If you have the coordinates, you can do calculations. You can get the distance with the Pythagorean formula; the x-point of the midpoint is the average of both x-coordinates, similar for the y-point.
Point A has coordinates (x,y). Point B (Point A rotated 270°) has coordinates (y,-x). Point C (horizontal image of Point B) has coordinates (-y,-x).
The solution is the coordinates of the point where the graphs of the equations intersect.
A point has coordinates; an angle does not.
oh my goodness not even dr.sheldon cooper can answer that
Converse: If the coordinates are positive, then the point is in the first quadrant
The point whose Cartesian coordinates are (2, 0) has the polar coordinates R = 2, Θ = 0 .