(3x^2 - 4y^2)(3x^2 + 4y^2)
2(8y + 1)
4(3y + 2)(7y - 6)
16y is 2 • 2 • 2 • 2 • y or 24y.
24 x y
4(y + 2)(y + 2)
This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)
4(y + 2)(y + 2)
It is: 28y -16y = 12y
It is: 28y -16y = 12y
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0
16y -64 as an inequality = -48
28y - 16y = 12y.