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Q: How do you factor 9x to the fourth power minus 16y to the fourth power?

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8x - 16y = 8*(x - 2y)

write the problem: 27x4-48x2y2factor out 4x from both: 4x(27-48y)factor out the 3's: 4x * 3 (9-16y)simplify: 12x(9-16y)if you want, factor out -1 to put y in front: -12x(16y-9)both answers are correct

2(8y + 1)

4(3y + 2)(7y - 6)

16y is 2 â€¢ 2 â€¢ 2 â€¢ 2 â€¢ y or 24y.

24 x y

4(y + 2)(y + 2)

This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)

It is: 28y -16y = 12y

It is: 28y -16y = 12y

16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0

4(y + 2)(y + 2)

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