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Any expression in the format (a2 - b2) is referred to as a "difference of squares". It can always be broken down into the format (√a + √b)(√a - √b).
In this case then, the square root of x2 is equal to x, and the square root of 9 is equal to three. We know then that:
x2 - 9 = (x + 3)(x - 3)
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How do you completely factor x to the fourth power minus eighty one?
Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).
Is x2-6x plus 9 can factor?
x2-6x+9 = (x-3)(x-3) when factorised.
What is the factor poloyonomial of 9 - x squared?
9 - x2 = 32 - x2 = (3 - x)(3 + x)
Factor x2 plus 9 plus 20?
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
Factor the following x2 plus 9?
x2 + 9 = (x + 3i)(x - 3i) The answer is based on a knowledge of imaginary and complex numbers where i2 = -1
Factor 9 - x2?
9 - x2 will factor into (3 - x)(3 + x)
How do you factor x2-9x?
x2-9x = x(x-9)
How do you completely factor x to the fourth power minus eighty one?
Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).
How do you factor x8-81?
(x2 - 3)(x2 + 3)(x4 + 9)
Is x2-6x plus 9 can factor?
x2-6x+9 = (x-3)(x-3) when factorised.
What is the factor poloyonomial of 9 - x squared?
9 - x2 = 32 - x2 = (3 - x)(3 + x)
What is the factor for x2-8x-9?
(x - 9)(x + 1)
What is the factor of x2-5x-6?
x -9
What is the factor of x2 - 9?
(x + 3)(x - 3)
Factor x2 plus 9 plus 20?
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
How do you factor 5x2 - 45?
To factor any term, divide by the LCF (largest common factor) of the term. For 5x2-45, the LCF is 5. 5x2-45 = 5(x2-9) It can, of course, be factored even further to become: 5(x2-9) = 45(x2/9 - 1) but when factoring, we usually don't need to go past 5(x2-9) (for example, you've figured out that x2 = 9, thus x = +/- 3.)
How do you factor x2-9x plus 8?
(x-9)(x+9)
