How do you factor y6 plus 1?

Answer 1

7 goes into both terms so take out a 7: 7(y+6)

Answer 2

y (y - 6) (y - 8)

y3 -14y2 +48y

=y (y2 - 14y + 48)

= y (y - 6) (y - 8)

Answer 3

y6 + 1 = (y2 + 1)(y4 - y2 + 1) which cannot be factorised further.

Answer 4

(y^2 + 1)(y^4 - y^2 + 1)

Answer 5

7(x - 2y - 3)

Answer 6

2y(y + 3)(y - 7)