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7 goes into both terms so take out a 7: 7(y+6)

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13y ago
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12y ago

y (y - 6) (y - 8)

y3 -14y2 +48y

=y (y2 - 14y + 48)

= y (y - 6) (y - 8)

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13y ago

y6 + 1 = (y2 + 1)(y4 - y2 + 1) which cannot be factorised further.

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9y ago

(y^2 + 1)(y^4 - y^2 + 1)

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12y ago

7(x - 2y - 3)

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9y ago

2y(y + 3)(y - 7)

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Q: How do you factor y6 plus 1?
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