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(x^2 - 9)
To factor this, we start off looking at the x^2. Since x^2 has no whole number in front of it (like 3x^2), then we know our factors are going to look like this:
(x );(x )
Now, what are the factors of -9? The factors of -9 are -1,1,-3,3,-9,9. Since our quadratic has no value that is multiplied by x [like (x^2 - 4x - 9)], then we know that the same numbers that multiply to make -9 must also add up to 0 (again, since there is no middle number multiplied by x). Therefore, the only factors of -9 that add to 0 and multiply to make -9 are... -3 and 3.
So, our factors are:
(x-3)(x+3)
Factorise it!
First you factorise it. Then you cancel out the common terms.
With the help of the quadratic equation formula
There are many ways: one is to factorise. If the quadratic is written as ax2 + bx + c then, if b2 = 4ac, the quadratic is a perfect square. It is (x - b/2a)2
Look in an advanced maths book.Improved answer:-If the discriminant of the quadratic expression is less than zero then it's not possible to factor it.