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Jaquelin Jast
Wiki User
∙ 14y ago(x^2 - 9)
To factor this, we start off looking at the x^2. Since x^2 has no whole number in front of it (like 3x^2), then we know our factors are going to look like this:
(x );(x )
Now, what are the factors of -9? The factors of -9 are -1,1,-3,3,-9,9. Since our quadratic has no value that is multiplied by x [like (x^2 - 4x - 9)], then we know that the same numbers that multiply to make -9 must also add up to 0 (again, since there is no middle number multiplied by x). Therefore, the only factors of -9 that add to 0 and multiply to make -9 are... -3 and 3.
So, our factors are:
(x-3)(x+3)
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How do you know if a quadratic equation will have whether or not it will have solutions?
Factorise it!
How do you solve quadratic?
First you factorise it. Then you cancel out the common terms.
How do you factorise 12x squared minus 9x minus 14?
With the help of the quadratic equation formula
How do you figure out if a quadratic equation is a perfect square?
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