0
(x^2 - 9)
To factor this, we start off looking at the x^2. Since x^2 has no whole number in front of it (like 3x^2), then we know our factors are going to look like this:
(x );(x )
Now, what are the factors of -9? The factors of -9 are -1,1,-3,3,-9,9. Since our quadratic has no value that is multiplied by x [like (x^2 - 4x - 9)], then we know that the same numbers that multiply to make -9 must also add up to 0 (again, since there is no middle number multiplied by x). Therefore, the only factors of -9 that add to 0 and multiply to make -9 are... -3 and 3.
So, our factors are:
(x-3)(x+3)
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How do you know if a quadratic equation will have whether or not it will have solutions?
Factorise it!
How do you solve quadratic?
First you factorise it. Then you cancel out the common terms.
How do you factorise 12x squared minus 9x minus 14?
With the help of the quadratic equation formula
How do you figure out if a quadratic equation is a perfect square?
There are many ways: one is to factorise. If the quadratic is written as ax2 + bx + c then, if b2 = 4ac, the quadratic is a perfect square. It is (x - b/2a)2
How do you know whether it is possible to factorise a quadratic expression?
Look in an advanced maths book.Improved answer:-If the discriminant of the quadratic expression is less than zero then it's not possible to factor it.
How do you know if a quadratic equation will have whether or not it will have solutions?
Factorise it!
How do you solve quadratic?
First you factorise it. Then you cancel out the common terms.
How do you factorise 12x squared minus 9x minus 14?
With the help of the quadratic equation formula
How do you figure out if a quadratic equation is a perfect square?
There are many ways: one is to factorise. If the quadratic is written as ax2 + bx + c then, if b2 = 4ac, the quadratic is a perfect square. It is (x - b/2a)2
How do you know whether it is possible to factorise a quadratic expression?
Look in an advanced maths book.Improved answer:-If the discriminant of the quadratic expression is less than zero then it's not possible to factor it.
How To Factor Trinomials?
Find one factor by substituting in values, then use long division. You can then apply the quadratic formula to the result - or factorise it by sight, of course
How do you factorise x2-11x-10?
This does not factor over the field of rational numbers. If does factor over the reals. Use the quadratic formula to find the roots for the related quadratic equation: x2-11x-10 = 0 Cal them r1 and r2. The factors are (x - r1) and (x - r2.)
What is the answer to 35x to the second plus 34x plus 8 when factoring?
Presumably this is a quadratic equation question in the form of 35x2+34x+8 = 0 35x2+34x+8 = 0 (7x+4)(5x+2) = 0 Answer: x = -7/4 or x = -2/5 Usually you can factorise a quadratic equation by trial and improvement but in this case it's quicker to use the quadratic equation formula.
Simplify 2t squared plus 8t plus 5 equals 0?
Let's simplify this together, friend. To solve the equation 2t^2 + 8t + 5 = 0, we can use the quadratic formula or factor it. If we factor, we look for two numbers that multiply to 2*5=10 and add up to 8. Once we find those numbers, we can rewrite the equation in factored form to find the solutions for t. Just take your time and enjoy the process of unraveling this mathematical mystery.
How do you factorise quadratic equations?
Well it is incredibly difficult and prctically impossible i think you should probably ask your teacher as this is physically impossible to answer by your self so yeah ask your teacher. sorry but it had to be said it took me ages.
What is the formula for calculating volumetric weight of a box?
Table dimension is 59"x35"x29" please calculate volumetric weight in KG Table dimension is 59"x35"x29" please calculate volumetric weight in KG {| |- | Volumetric WeightVolumetric WeightVolumetric Weight * Volumetric Weight|}
How do you factorise a quadratic equation that starts without a number?
The question is not phrased clearly enough to answer exactly; what does "starts with a number" mean?If you mean not starting with a constant number at the beginning, this is common, as most functions are written in order of the highest power of the variable first; you will first need to rearrange the expression to a suitable order.If you mean that the x2 or x terms do not have coefficients (numbers written next to them as ab, meaning "a multiplied by b") then these are easier to factorise; a lack of coefficient simply means "multiplied by one". Further questions can explain how to factorise further.
