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The way I would do it is find a vector whose "Dot product" with the given vector is zero. Given vector ; R = 7i - 3j Unknown vector ; F = ai + bj Dot product = 0 = F(dot)R = 7a -3b; this means b = (7/3)a , for any value of a , so F = ai + (7/3)aj and you can use any value for "a". Picking values for "a" will not change the direction of F, just its magnitude. You can show this by finding the tangent of the angle F makes with horizontal; Tan(A) = Fy/Fx = b/a = (7/3)a/a, = 7/3, constant, independent of "a" .
The velocity at each point in the fluid is a vector. If the fluid is compressible, the divergence of the velocity vector is nonzero in general. In a vortex the curl is nonzero.
Vectors are identified by magnitude, or the length of the line, and direction, represented by the arrowhead pointing toward the terminal point. The position vector has an initial point at (0,0) and is identified by its terminal point ⟨a,b⟩.
Consider the Complex Plane, with Real numbers along the horizontal axis, and Pure Imaginary numbers on the vertical axis. Any Complex number (a + ib) can be plotted as a point (a,b) on this plane. The point can be represented as a vector from the 'origin' (0,0) to the point (a1,b1). If the second 'complex vector' (a2,b2) is added to the first, this can be shown as a translated vector with it's 'tail' starting at the arrowhead of the first vector, and then the arrowhead of the second vector will terminate at the sum of: a1 + ib1 + a2+ ib2 [coordinate point: (a1+a2,b1+b2)
You cannot, unless it is a null vector. As a point.
Vector
The velocity at each point in the fluid is a vector. If the fluid is compressible, the divergence of the velocity vector is nonzero in general. In a vortex the curl is nonzero.
Vectors are identified by magnitude, or the length of the line, and direction, represented by the arrowhead pointing toward the terminal point. The position vector has an initial point at (0,0) and is identified by its terminal point ⟨a,b⟩.
Using the term "trajectory" implies that the acceleration you are concerned about is due to gravity. Gravity will always be perpendicular to the surface. Unless the trajectory begins perpendicular to the surface, it will never change to become perpendicular and the velocity will never be in a direction parallel to the acceleration. If it starts perpendicular to the surface it will start and remain perpendicular. Of course if you have another force acting on the object - such as wind - the component of the velocity vector parallel to the ground could be reduced to zero and at that point the only remaining component of the velocity vector would be that perpendicular to the ground and parallel to the acceleration. Likewise if the object is being propelled by an engine or rocket, the trajectory could be parallel to the force any time the acceleration vector became parallel to the velocity vector.
The component form of a vector lists the horizontal and vertical change from the initial point to the terminal point. * * * * * The axes need not be perpendicular to one another. They just need to be non-parallel.
VECTOR
true the distance from point A to point B on a grid = vector
Point Perpendicular Light was created in 1899.
The difference is the length of the vector.
Biconditional Statement for: Perpendicular Bisector Theorem: A point is equidistant if and only if the point is on the perpendicular bisector of a segment. Converse of the Perpendicular Bisector Theorem: A point is on the perpendicular bisector of the segment if and only if the point is equidistant from the endpoints of a segment.
Consider the Complex Plane, with Real numbers along the horizontal axis, and Pure Imaginary numbers on the vertical axis. Any Complex number (a + ib) can be plotted as a point (a,b) on this plane. The point can be represented as a vector from the 'origin' (0,0) to the point (a1,b1). If the second 'complex vector' (a2,b2) is added to the first, this can be shown as a translated vector with it's 'tail' starting at the arrowhead of the first vector, and then the arrowhead of the second vector will terminate at the sum of: a1 + ib1 + a2+ ib2 [coordinate point: (a1+a2,b1+b2)
Draw a vector from his starting point to his ending point.
There is no point A and so nothing is represented.