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One way to do it is to write down all the numbers and add them up. You can do it.

Another more clever way to do it is to arrange them in pairs, like this:

1 and 50

2 and 49

...

24 and 27

25 and 26

Every pair adds up to 51, and there are 25 pairs. So all together, they add up to

51 x 25 = 1,275 .

2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50

Subtract the odd numbers between 10 and 14.

Q: How do you find out the sum of all the numbers from 1-50?

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sum of 150 what? first 150 numbers?

5625

1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75

50

The sum is 150*151/2 = 11,325

The average of the three numbers is 50, so the other two must be 48 and 52.

Add all the numbers together and that's the sum. The sum is the answer.

int sum (int from, int to, int step){if (from>to) return 0;else return from + sum (from+step, to, step);}...n = sum (2, 150, 2);

To find the mean, you find the average of the numbers. This means that you just add all of the numbers and then divide that sum by how many numbers are in the list. The sum of all the numbers is 120 which you can then divide by 7 to get 17.143.

The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.

The sum of a fraction? Well, to find the sum of the fraction all you do is divide both top and bottom numbers.

The numbers are -150 and -148.