sum of 150 what? first 150 numbers?
5625
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
50
The sum is 150*151/2 = 11,325
The average of the three numbers is 50, so the other two must be 48 and 52.
Add all the numbers together and that's the sum. The sum is the answer.
int sum (int from, int to, int step){if (from>to) return 0;else return from + sum (from+step, to, step);}...n = sum (2, 150, 2);
To find the sum of all numbers from 51 to 150, we can use the formula for the sum of an arithmetic series: (n/2)(first term + last term), where n is the number of terms. In this case, the first term is 51, the last term is 150, and the number of terms is 150 - 51 + 1 = 100. Plugging these values into the formula, we get (100/2)(51 + 150) = 50 * 201 = 10,050. Therefore, the sum of all numbers from 51 to 150 is 10,050.
To find the mean, you find the average of the numbers. This means that you just add all of the numbers and then divide that sum by how many numbers are in the list. The sum of all the numbers is 120 which you can then divide by 7 to get 17.143.
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
To answer this question I will use an example. Data set: 10, 20, 30, 40, 50. First find the sum of all the numbers...so 10+20+30+40+50= 150. Then you take the sum (150) and divide it by the number of numbers in the data set. So 150 divided by 5 (the number of numbers in this data set) = 30. 30= the mean of the above data set. Finding the mean is pretty simple. :)