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You first plot the line -2y = -x - 2
(or equivalently, 2y = x + 2).
At the origin = (0,0),
-2*0 = 0 ≤ -0-2 = -2
So the inequality to be plotted is FALSE. Since (0,0) lies below the line, the region below the line is not required. Thus the graph is the solid line of the equation as well as the region above it.
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First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
It is then 2y
If you mean 2y = -5x+14 then y = -2.5x+7 whereas -2.5 is the slope and 7 is the y intercept
Put in this form.......Y = mX + bb = Y intercept.3X - 2Y = 6- 2Y = - 3X + 6Y = (3/2)X - 3================