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Ramon Anderson

Lvl 10
βˆ™ 3y ago
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βˆ™ 11y ago

You first plot the line -2y = -x - 2

(or equivalently, 2y = x + 2).

At the origin = (0,0),

-2*0 = 0 ≤ -0-2 = -2

So the inequality to be plotted is FALSE. Since (0,0) lies below the line, the region below the line is not required. Thus the graph is the solid line of the equation as well as the region above it.

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Q: How do you graph -2y is less than or equal to -x-2?
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