It is then 2y
x = 2y y = x - 2 or x = 2y subtract 2y to both sides x - 2 = y subtract y and add 2 to both sides x - 2y = 0 multiply by -1 to both sides x - y = 2 -x + 2y = 0 x - y = 2 add these two equations together y = 2 substitute 2 for y into the first equation, x = 2y x = 2(2) = 4 Thus the solution of these linear system of equations is the point (4, 2). Check:
x would equal -1 and y would equal 1
3xy-2y=0 3xy=2y y=2y (3x) y/2y=3x 1/2=3x multiply across by 2 1=6x 1/6=x therefore substituting x=1/6 into 3xy-2y; 3(1/6)y-2y=0 1/2y=2y y=2y/0.5 0.5 aka 1/2 y=1
2y - 4x = -12 Algebraically rearrange to 2y = 4x - 12 Divide both sides by '2' y = 2x - 6 So at the 'y' intercept, x = 0 Substituting x = 0 We have y = 2(0) - 6 Anything multiplied '0' is equal; to '0' Hence y = 0 - 6 y = -6 is the value of the y-intercept.
If 2y = 2628, 2628/2 = 1314, Therefore y = 1314.
2y
what is c, x + 2y, x+y equal to or greater than 8, x equal to or greater than 3, y equal to or greater than 0.
X + ( 2Y - 2X - Y ) is equal to Y - X
5+y+2y? = 5+3y?
5
10-y=2y+3 10-3=2y+y 7=3y 7/3=y
It is then 2y
y=-7 but I have no idea on how to get it
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
3x + 2y = x + y y = -2x to find y-int set x equal to zero y = -2(0) = 0 or... 3(0) + 2y = (0) + y 2y - y = 0 y = 0 y-intercept is zero
(13-2y)/8