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Sibyl Quitzon
Wiki User
∙ 11y agoWhen x = 0, the equation becomes 3y = -2 or y = -2/3
Mark the point P = (0, -2/3)
When y = 0, the equation becomes 0 = x-2 or x = 2
Mark the point Q = (2, 0)
Join the two points P and Q and extend the line in both directions.
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How Do you Graph The Following Equation -2x plus 3y equals 1?
-2x plus 3y equals 1
Manuel says that the graph of 3y-36 equals 2x2-18x is an ellipse with its major axis parallel to the y-axis Shanice disagrees Who is correct?
3y - 37 = 2x2 - 18x3y = 2x2 - 18x + 37y = (2/3)x2 - 6x + (37/3)The graph is a parabola.Shanice outshines Manuel.
X2 plus 3xy - 18y2 equals?
(x + 6y)(x - 3y)
What is the effect on the graph of the equation y equals x2 plus 2 when it is changed to y equals x2 - 4?
the graph is moved down 6 units
How do you graph x equals 8y over 2x plus 3y equals 38?
7
Is 3y equals x2-8 linear?
yes.
What describes the translation of the graph of y equals x2 to obtain the graph of y equals -x2 - 3?
No translation will invert a quadratic graph.
How Do you Graph The Following Equation -2x plus 3y equals 1?
-2x plus 3y equals 1
Manuel says that the graph of 3y-36 equals 2x2-18x is an ellipse with its major axis parallel to the y-axis Shanice disagrees Who is correct?
3y - 37 = 2x2 - 18x3y = 2x2 - 18x + 37y = (2/3)x2 - 6x + (37/3)The graph is a parabola.Shanice outshines Manuel.
X2 plus 3xy - 18y2 equals?
(x + 6y)(x - 3y)
What is the effect on the graph of the equation y equals x2 plus 2 when it is changed to y equals x2 - 4?
the graph is moved down 6 units
How do you graph x equals 8y over 2x plus 3y equals 38?
7
What does the graph of the equation 2x-3y equals 6 look like?
The equation 2x - 3y = 6 is a linear equation and a linear equation is always has a straight line as a graph
What is the graph of y equals x2-7?
9
What is the vertex of the function y equals x2 plus 6x-5?
x = -3y = -14
What is the vertex of the graph of the function y equals x2-4x plus 3?
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).
How do you graph y equals x2?
The graph is a parabola facing (opening) upwards with the vertex at the origin.
