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3y = x - 2
First of all divide through nby '3'
Hence
y = (1/3)x - ( 2/3).
For the general form of a straight line is y = mx + c
'm' is the gradient/slope
'c' is the y-intercept.
So in this case , the slope/gradient is '1/3' and the y-intercept is ' -2/3 '.
So on you graph paper., go to the y- axis, and find the point '-2/3' , this is below the x-axis.
Its coordinates are ( 0, -2/3) . Then go along the x-axis to the point x = 1 . Go below this point to a position, where the graph line has raised by '1/3' , The coordinates are ( 1, -1/3) .
As you now have to coordinate positions, you can draw a straight line between them , and then extrapolate that same line in either direction..
When x = 0, the equation becomes 3y = -2 or y = -2/3
Mark the point P = (0, -2/3)
When y = 0, the equation becomes 0 = x-2 or x = 2
Mark the point Q = (2, 0)
Join the two points P and Q and extend the line in both directions.
-2x plus 3y equals 1
(x + 6y)(x - 3y)
the graph is moved down 6 units
3y - 37 = 2x2 - 18x3y = 2x2 - 18x + 37y = (2/3)x2 - 6x + (37/3)The graph is a parabola.Shanice outshines Manuel.
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