2
5/8 x1/20 = 1/32
2
Two points: (x1, y1) and (x2, y2), Then formula would be: y2 - y1 (over) x2 - x1
The distance between the points (1, 2) and (x1, y1) is calculated using the distance formula, which is derived from the Pythagorean theorem. Specifically, the distance ( d ) is given by ( d = \sqrt{(x1 - 1)^2 + (y1 - 2)^2} ). This expression represents the length of the line segment connecting the two points in a Cartesian plane.
First of all, find the total number of not-necessarily distinguishable permutations. There are 12 letters in hippopotamus, so use 12! (12 factorial), which is equal to 12 x 11x 10 x9 x8 x7 x6 x5 x4 x3 x2 x1. 12! = 479001600.Then count the of each letter and calculate how many permutations of each letter can be made. For example, here is 1 h, so there is 1 permutation of 1 h.H 1I 1P 60 2T 1A 1M 1U 1S 1Multiply these numbers together. 1 x1 x6 x2 x1 x1 x1 x1 x1 = 12Divide 12! by this number. 479001600 / 12 = 39,916,800 Distinguishable Permutations.
If the variables are x1 & x2 the solution is : 1) x1=x1+x2; 2) x2=x1-x2; 3) x1=x1-x2; EX: x1=1 , x2=6; 1) x1= 1+6 = 7 2) x2= 7-6 =1 3 x1=7-1 =6 ============================================
Slope= Y2-Y1 over X2-X1.for example the slope of the points (2,2) & (1,0) m=y2-y1 over x2-x1 =0-2 over 1-2 =-2/-1 =2
Under the hood, in the fuse panel. There's probably a cover over it with a thumbscrew. The relay will probably be 1"x1" or 1"x1/2"
sqr.rtx/x= sqrt.x*sqr.rtx/sqr.rtx=x/x*sqrt.x=1/sqrt.x. x1/2 = x1/2 * x1/2 = x = 1 (x1/2) /x= 1/x1/2
5/8 x1/20 = 1/32
2
no, its subtraction. if x2 is over x to the first power, the exponent at the higher value subtracts the x1. whether the x2 is above or below x1, x1 is always being subtrated from x2. X2 X(1) x __ OR __ = X or _ X(1) X2 1
X2 jumps over X1's lightsaber and X1 kills himself
it equals x1 it equals x1
1"x1"
The answer depends on absolute deviation from what: the mean, median or some other measure. Suppose you have n observations, x1, x2, ... xn and you wish to calculate the sum of the absolute deviation of these observations from some fixed number c. The deviation of x1 from c is (x1 - c). The absolute deviation of x1 from c is |x1 - c|. This is the non-negative value of (x1 - c). That is, if (x1 - c) ≤ 0 then |x1 - c| = (x1 - c) while if (x1 - c) < 0 then |(x1 - c)| = - (x1 - c). Then the sum of absolute deviations is the above values, summed over x1, x2, ... xn.
To find out you do Y2-Y1 over X2-X1.... 1-(-1)/-1-1...... 1-(-1)=2 -1-1=-2 the slope is 2over-2