Slope= Y2-Y1 over X2-X1.for example the slope of the points (2,2) & (1,0)
m=y2-y1 over x2-x1
=0-2 over 1-2
=-2/-1
=2
Use point-slope formula
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
Without an equality sign the given terms can't be considered to be a straight line equation.
5
Use point-slope formula
we have to change the given equation to y=mx+b.here m is the slope
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
y = {slope}x + {y intercept}
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
If you mean: y = 3.8x then the slope is 3.8 with no y intercept
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
Use: (y2 -y1)/(x2 -x1) to find the slope. Use: y -y1 = m(x -x1) to find the slope intercept equation whereas m is the slope.
You have to differentiate the equation. The dy/dx is the slope.
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
To identify the slope in a linear equation, rearrange the equation into the form y = mx + b. The term m is the slope.