4x-1 = 6x-15 4x-6x = 1-15 -2x = -14 x = 7
4x - 1 = 9(+ 1 on both sides)4x = 10(Divide both sides by 4)x = 2.5
x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i
6x - 30 = 4x + 1 Subtract 4x + 1 from each side giving 2x - 31 = 0 so x = 15.5
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
How do you solve y=-4x+1
4x-1 = 6x-15 4x-6x = 1-15 -2x = -14 x = 7
-1-2x-4x=19-6x-1 = -19x = 3
16x³ - x = 0 By factorization, we obtain: x(16x² - 1) = 0 x(4x - 1)(4x + 1) = 0 Set each term by 0 and solve for x to get: x = 0 and 4x - 1 = 0 and 4x + 1 = 0 x = {0, ±¼}
8x-1=23-4x 12x=24 x=2
4x - 1 = 9(+ 1 on both sides)4x = 10(Divide both sides by 4)x = 2.5
4X = 16X2 4X - 16X2 = 0 (1 - 4X)4X = 0 ------------------ as you see X = 0 -------- 1 - 4X = 0 - 4X = - 1 X = 1/4 ----------- So, X = 0 and X = 1/4. You check.
3x = 7 - 4x 3x + 4x = 7 - 4x + 4x 7x = 7 7x/7 = 7/7 x = 1
1x-5x = -4x But since you had the absolute value symbols surrounding it, change it to positive; so the answer is: 4x
-6x, -4x =
x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i
Subtract 4x from each side getting 1 = 48x so x = one forty-eighth