4
You have two equations. They are...
x=y+6 Equation (1)
y=-2-x Equation (2)
Since you know what "y" is you can solve by substitution. Substitute the second equation into the first.
x=(-2-x) + 6
x=4-x
2x=4
x=2
Now plug "x" into the second equation to find "y"
y=-2-2
y=-4
Now plug both "x" and "y" into both equations to see if I did them correctly
2=-4+6
2=2 Correct!
-4=-2-2
-4=-4 Correct!
So x=2 and y=-4 are the correct answers.
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
X=6
12 = 2x + 6 subtract 6 from both sides 6 = 2x divide both sides by 2 3 = x
this can not be solved un less with another equation
Yes and it works out that x = 3 and y = 4
22+2x = 37+6+x 2x-x = 37+6-22 x = 21
2x+8 = 6 2x = 6-8 2x = -2 x = -1
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
2x + 7 = 1 Therefore, 2x = -6 x = -6/2 x = -3
X=6
12 = 2x + 6 subtract 6 from both sides 6 = 2x divide both sides by 2 3 = x
4x=-10 x=-2.5
Yes, they are. If you solve 2x + 7y = 6 for y, you get y = (-2x + 6) / 7. If you solve 7y + 2x + 6 = 0 for y, you get y = (-2x - 6) / 7. As you can see, both equations have the same slope. Therefore they are parallel. You can punch those equations into a graphing calculator and visually verify that they are indeed parallel.
To solve this equation we have to isolate and solve for x. So: 2x-6= x+5 +6 +6 2x = x+11 -x -x x = 11 So x=11.
this can not be solved un less with another equation
Yes and it works out that x = 3 and y = 4
3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6