How do you solve the following equation using identities sin2x-sinx equals 0?

Answer 1

2

Answer 2

sin 2x - sin x = 0 (substitute 2sin x cos x for sin 2x)
2sin x cos x - sin x = 0
sin x(2cos x - 1) = 0
sin x = 0
x = 0⁰, x = 180⁰ in a period of 360⁰, so that
x = 0⁰ + 360⁰n, x = 180⁰+ 360⁰n, where n is any integer
or
2cos x - 1 = 0
cos x = 1/2
x = 60⁰, x = 300⁰ in a period of 360⁰, so that
x = 60⁰ + 360⁰n, x = 300⁰ + 360⁰n, where n is any integer