0 = 0 is an identity and not an equation. Equations have solutions, identities do not.
It has 2 real solutions because the discriminant is greater than zero.
There are no real solutions because the discriminant of the quadratic equation is less than zero.
x = -½
None.Whatever number you substitute for 'x', 0x will always be 0,and the equation will always become [ 0 = 4 ].No value of 'x' can make [ 0 = 4 ]. There is no solution.
It has infinitely many solutions.
It has two equal solutions of 2
It has two solutions and they are: x = 3.230396696 and x = -2.063730029
6z - 3 = 0
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
Two solutions and they are:- x = 0 and y = 3
There are no real solutions. The discriminant (b squared -4ac) is less than 0, so there are 2 imaginary solutions and 0 real ones.
There are two solutions for x: x=11 and x=-7
x2-10 = 0 x2 = 10 x = the square root of 10
There are four solutions to 9x4 plus 27x3 - 4x2 - 12x equals 0. One of the solutions is x = -3.