How do you verify 1 divided by cos to the second theta minus tan to the second theta equals cos to the second theta plus 1 divided by csc to the second theta?

Answer 1

2

Answer 2

Verify the identity:

1/(cos θ)^2 - (tan θ)^2 = (cos θ)^2 + 1/(csc θ)^2

1/(cos θ)^2 - (sin θ)^2/(cos θ)^2 = (cos θ)^2 + (sin θ)^2 ?

1 - (sin θ)^2/(cos θ)^2 = (cos θ)^2 + (sin θ)^2 ?

(cos θ)^2/(cos θ)^2 = 1 ?

1 = 1 True

Method 2

1/(cos θ)2 - (tan θ)2 =? (cos θ)2 + 1/(cscθ)2

1/(cos θ)2-(sinθ)2/(cos θ)2=? (cosθ)2+ sin(θ)2

1/(cos θ)2[1-sin(θ)2]=? cos(θ)2+sin(θ)2

1/cos(θ)2(cos(θ)2)=? 1

1=1 True