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First find the midpoint and slope of points (h, k) and (3h, -5k)
Midpoint = (h+3h)/2, (6k+k)/2 = (2h, -2k)
Slope = (-5k-k)/(3h-h) = -6k/2h = -3k/h
Then find the perpendicular slope which is the positive reciprocal of -3k/h which is h/3k
Then substitute these values into the formula of y-y1 = m(x-x1) :-
y-(-2k) = h/3k(x -2h)
y = hx/3k -2h2/3k -2k
Multiply all terms by 3k and the perpendicular bisector equation can be expressed in the form of :-
hx -3ky -2h2 -6k2 = 0
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
That is the equation of a straight line intersecting the axis at (4,0) and (0,-4). There is no "answer" as such; an "answer" would imply that you require specific values for x and y at a certain place (e.g where this line meets another line), which clearly cannot be answered with the details given: you have two variables (x and y) and one equation. You MUST have at least the same number of equations as variables in order to solve for x, y etc...
The question seems to be missing some context or a specific equation relating x and y. To determine the value of y when x = 6, you'll need to provide the equation or relationship between x and y. Please provide more details for an accurate answer.
The graph is a straight line, because there's no x2 or y2 in the equation.Now give us a second to massage it around a bit, and then we'll show you howyou can tell the line's details easily. We're not changing anything, just presentingit in a different light:-6x + 2y = -2Add 6x to each side of the equation:2y = 6x - 2Divide each side by 2:y = 3x - 1That's exactly the same equation, but you can look at this form and see immediatelythat the slope of the line is 3, and it cuts the y-axis at the point [ y= -1 ].