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How do you work out the equation for the perpendicular bisector of the straight line joining h k and 3h -5k showing details of your work?
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What is the perpendicular bisector equation passing through the line segment of 7 7 and 3 5 giving brief details?
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
Write the equation of the line that goes through the point 0 -4 with slope m equals -2?
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
What is the answer to x-y equals 4?
That is the equation of a straight line intersecting the axis at (4,0) and (0,-4). There is no "answer" as such; an "answer" would imply that you require specific values for x and y at a certain place (e.g where this line meets another line), which clearly cannot be answered with the details given: you have two variables (x and y) and one equation. You MUST have at least the same number of equations as variables in order to solve for x, y etc...
What is the value of y when x 6?
The question seems to be missing some context or a specific equation relating x and y. To determine the value of y when x = 6, you'll need to provide the equation or relationship between x and y. Please provide more details for an accurate answer.
What is -6x plus 2y equaling -2 on a graph look like?
The graph is a straight line, because there's no x2 or y2 in the equation.Now give us a second to massage it around a bit, and then we'll show you howyou can tell the line's details easily. We're not changing anything, just presentingit in a different light:-6x + 2y = -2Add 6x to each side of the equation:2y = 6x - 2Divide each side by 2:y = 3x - 1That's exactly the same equation, but you can look at this form and see immediatelythat the slope of the line is 3, and it cuts the y-axis at the point [ y= -1 ].
What is the perpendicular bisector equation passing through the line segment of 7 7 and 3 5 giving brief details?
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
What is the perpendicular bisector equation joining the line segment of -2 plus 5 and -8 -3 giving brief details?
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
How do you form an equation for the perpendicular bisector of the line segment joining the points of p q and 7p 3q showing all details of your work?
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
What is the equation of the straight line that extends from the origin to the centre of the points 3 2 and 5 -1 on the Cartesian plane giving thorougher details of your work?
The equation is y = 1/8x because there is no y intercept and by doing some homework you'll find it correct
Write the equation of the line that goes through the point 0 -4 with slope m equals -2?
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
Which sequence of coefficient should be placed in the blanks to balance this equation?
I'm not sure which equation you are referring to. Could you please provide more details or specify the equation you are asking about?
How do you compute quadratic equation in qbasic programming?
See the related link for details.
How do you solve rational equations?
The details really depend on the equation. It often helps to multiply all parts of the equation by a common denominator, to get rid of the fractions.
What is the value of y in the equation 6.4x 2.8y 44.4 when x 3?
Without an equality sign and other information the details given can't be considered to be an equation.
How do you swap a 1976 350 to a 1986 305?
Should be a straight swap. Are you looking for specific details?
What are the steps to solving a radical equation?
Details may vary depending on the equation. Quite often, you have to square both sides of the equation, to get rid of the radical sign. It may be necessary to rearrange the equation before doing this, after doing this, or both. Squaring both sides of the equation may introduce "extraneous" roots (solutions), that is, solutions that are not part of the original equation, so you have to check each solution of the second equation, to see whether it is also a solution of the first equation.
What is meant by skeletal chemical equation?
A skeletal chemical equation is a simplified version of a chemical equation that omits details about the physical state of the reactants and products, as well as the coefficients of the compounds involved. It focuses on showing only the essential elements and their ratios in the reaction.
