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Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
The equation provided, "3xy6," seems to be a typo or incorrect format. If we assume you meant a line in the form of ( y = mx + b ), where ( m ) is the slope, the slope of a line perpendicular to it would be the negative reciprocal of ( m ). If more details or clarification on the equation are provided, I can give a more specific answer.
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
It seems like your question got cut off. Could you please provide more details or clarify what type of equation you are asking about? This will help me give you the best answer possible!
That is the equation of a straight line intersecting the axis at (4,0) and (0,-4). There is no "answer" as such; an "answer" would imply that you require specific values for x and y at a certain place (e.g where this line meets another line), which clearly cannot be answered with the details given: you have two variables (x and y) and one equation. You MUST have at least the same number of equations as variables in order to solve for x, y etc...
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
The equation provided, "3xy6," seems to be a typo or incorrect format. If we assume you meant a line in the form of ( y = mx + b ), where ( m ) is the slope, the slope of a line perpendicular to it would be the negative reciprocal of ( m ). If more details or clarification on the equation are provided, I can give a more specific answer.
The equation is y = 1/8x because there is no y intercept and by doing some homework you'll find it correct
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
I'm not sure which equation you are referring to. Could you please provide more details or specify the equation you are asking about?
See the related link for details.
The details really depend on the equation. It often helps to multiply all parts of the equation by a common denominator, to get rid of the fractions.
Without an equality sign and other information the details given can't be considered to be an equation.
It seems like your question got cut off. Could you please provide more details or clarify what type of equation you are asking about? This will help me give you the best answer possible!
Should be a straight swap. Are you looking for specific details?