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How do you work out the equation for the perpendicular bisector of the straight line joining h k and 3h -5k showing details of your work?
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What is the perpendicular bisector equation passing through the line segment of 7 7 and 3 5 giving brief details?
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
What is the slope of a line perpendicular to the line whose equation is 3xy6. Fully reduce your answer.?
The equation provided, "3xy6," seems to be a typo or incorrect format. If we assume you meant a line in the form of ( y = mx + b ), where ( m ) is the slope, the slope of a line perpendicular to it would be the negative reciprocal of ( m ). If more details or clarification on the equation are provided, I can give a more specific answer.
Write the equation of the line that goes through the point 0 -4 with slope m equals -2?
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
What wrong with the equation in number 6?
Without specific details about the equation in question number 6, it's difficult to provide an accurate answer. However, potential issues could include incorrect operations, misapplied mathematical principles, or errors in numerical values. Please provide more context or details about the equation for a more precise analysis.
What is an equation that?
It seems like your question got cut off. Could you please provide more details or clarify what type of equation you are asking about? This will help me give you the best answer possible!
What is the perpendicular bisector equation passing through the line segment of 7 7 and 3 5 giving brief details?
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
What is the perpendicular bisector equation joining the line segment of -2 plus 5 and -8 -3 giving brief details?
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
How do you form an equation for the perpendicular bisector of the line segment joining the points of p q and 7p 3q showing all details of your work?
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
What is the slope of a line perpendicular to the line whose equation is 3xy6. Fully reduce your answer.?
The equation provided, "3xy6," seems to be a typo or incorrect format. If we assume you meant a line in the form of ( y = mx + b ), where ( m ) is the slope, the slope of a line perpendicular to it would be the negative reciprocal of ( m ). If more details or clarification on the equation are provided, I can give a more specific answer.
What is the equation of the straight line that extends from the origin to the centre of the points 3 2 and 5 -1 on the Cartesian plane giving thorougher details of your work?
The equation is y = 1/8x because there is no y intercept and by doing some homework you'll find it correct
Write the equation of the line that goes through the point 0 -4 with slope m equals -2?
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
Which sequence of coefficient should be placed in the blanks to balance this equation?
I'm not sure which equation you are referring to. Could you please provide more details or specify the equation you are asking about?
How do you compute quadratic equation in qbasic programming?
See the related link for details.
How do you solve rational equations?
The details really depend on the equation. It often helps to multiply all parts of the equation by a common denominator, to get rid of the fractions.
What wrong with the equation in number 6?
Without specific details about the equation in question number 6, it's difficult to provide an accurate answer. However, potential issues could include incorrect operations, misapplied mathematical principles, or errors in numerical values. Please provide more context or details about the equation for a more precise analysis.
What is the value of y in the equation 6.4x 2.8y 44.4 when x 3?
Without an equality sign and other information the details given can't be considered to be an equation.
What is an equation that?
It seems like your question got cut off. Could you please provide more details or clarify what type of equation you are asking about? This will help me give you the best answer possible!
