If you consider each set of 4 digits as a unique code regardless of numeric order (the code 0123 would be counted as a different code than 0132, 0213, 0231, 0312, 0321, 1023, 1032, 1203, 1230, 1230, etc.), there are 3,528 possible codes in the base 10 system containing the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.
100,000 - Every number from 00000 to 99999.
The Codes was created in 1966.
the repeated digits can lie in any of 3 positions:XXYZ,YXXZ, or YZXXTherefore, the number of different possible repeated digit combinations is 10×3=30 (there are 10 different possible digits).There are then 9 values left that Y could be, after the X's have their values, and 8 values left that Z could be, to ensure no unintended repeated numbers.This gives (10×3)×9×8=2160. There are therefore 2160 possible codes.
Any 4 from 10 in any order = 10 x 9 x 8 x 7 = 5040
The number of 3-letter codes that can be formed without repetition is equal to the number of choices for the first letter (4 letters), multiplied by the number of choices for the second letter (3 letters), multiplied by the number of choices for the third letter (2 letters). Therefore, the total number of 3-letter codes that can be formed is 4 x 3 x 2 = 24.
Clash of the Codes was created in 1994.
Codes in the Clouds was created in 2007.
If you include 0000, ten thousand unique four digit codes are possible.
104 = 10000 if digits can be repeated, 5040 if not. The above answers assume a code can start with a 0. If not, 9000 if digits can be repeated and 4536 if not.
The number codes are to unlock clues on the website at the39clues.com
The number of 4 digit codes, using different digits, is 10*9*8*7 = 5040. However, computer passwords can, usually, have repeated digits and, if that is allowed, you can have 104 = 10000 codes.
The answer is 720 different area codes. This is how you calculate it. There are 10 different numbers for the first category, then 9 for the second and 8 for the third, then you multiply those numbers in this order: 10 x 9=90, then 90 x 8=720.