How many 4 number combinations are there in 33 numbers?

Answer 1

Assuming there is no repetition, you want the number of groups of 4 numbers, and the order doesn't matter: this is calculated as 33 over 4; which is the same as (33 x 32 x 31 x 30) / (1 x 2 x 3 x 4)

Answer 2

Assuming there are no repeats in the 33 numbers, then the number of combinations is:

₃₃C₄ = 33!/(33-4)!4! = (33 × 32 × 31 × 30)/(4 × 3 × 2 × 1) = 40,920