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Oh, dude, let me grab my calculator for this super thrilling math question. So, you've got 9 numbers and you're trying to figure out how many ways you can arrange them. That's like 362,880 combinations, but who's counting, right? Just a casual number of possibilities for your 9-digit number extravaganza.
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ReneTo calculate the number of 9-digit combinations that can be made from the numbers 1-9 without repetition, we use the permutation formula. Since there are 9 numbers and we are choosing 9 without repetition, the formula is 9P9 = 9! / (9-9)! = 9! / 0! = 9! = 362,880. Therefore, there are 362,880 9-digit combinations that can be made from the numbers 1-9.
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If using numbers 0 through 9 how many different 2 digit combinations can be made?
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
How many 4 digit combinations can be made from 10 numbers with out repeating?
The answer is 10C4 = 10!/[4!*6!] = 210
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
How many different 3 digit combinations can be made using numbers one through nine?
Through the magic of perms and coms the answer is 729
If using numbers 1 thru 49 how many 6 digit combinations can be made?
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
