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To calculate the number of 9-digit combinations that can be made from the numbers 1-9 without repetition, we use the permutation formula. Since there are 9 numbers and we are choosing 9 without repetition, the formula is 9P9 = 9! / (9-9)! = 9! / 0! = 9! = 362,880. Therefore, there are 362,880 9-digit combinations that can be made from the numbers 1-9.
If the numbers are not allowed to repeat themselves then 362,880.
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That is the number of permutations, not combinations.
In a combination the order of the digits does not matter. So there is only one 9-digit combination.
I did 1×2×3×4×5×6×7×8×9 and got 362,880
362,880
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If using numbers 0 through 9 how many different 2 digit combinations can be made?
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
How many 4 digit combinations can be made from 10 numbers with out repeating?
The answer is 10C4 = 10!/[4!*6!] = 210
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
How many different 3 digit combinations can be made using numbers one through nine?
Through the magic of perms and coms the answer is 729
If using numbers 1 thru 49 how many 6 digit combinations can be made?
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
How many seven digit numbers can be made from numbers 123456789 but no repeatition of numbers allowed?
It would be from 1111111 to 9999999, and because 9999999 - 1111111 = 8888888, the answer is 8888888.
How many 4 digit combinations can be made using numbers 1 2 3 4 6?
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
How many different combinations can be made of 9 digit social security numbers can be made?
10 Combinations (if order doesn't matter). 3,628,800 Possiblilities (if order matters).
How many 7 digit combinations can be made using the numbers 1 through 9?
It is: 9C7 = 36
If using numbers 0 through 9 how many different 4 digit combinations can be made?
66
If using numbers 1 through 4 how many different 4 digit combinations can be made?
10,000
If using numbers 1 through 8 how many different 4 digit combinations can be made?
15
How many three digit combinations can be made from the numbers 9 3 and 1?
6 ways: 931,913,139,193,391,319
If using numbers 0 through 9 how many different 2 digit combinations can be made?
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
How many 4 digit combinations can be made from 10 numbers with out repeating?
The answer is 10C4 = 10!/[4!*6!] = 210
How many 2 digit combinations can be made from 3 numbers combined?
Only three: 12, 13 and 23. Remember that the combinations 12 and 21 are the same.
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
