Assume the water is initially at 40 F and 14.7 psia.
m = ( 1.0 gal ) ( 1.0 ft^3 /7.4805 gal ) ( 62.43 lbm / ft^3 ) = 8.346 lbm
Q = Delta U = ( m ) ( Cv ) ( T2 - T1 )
Q = ( 8.346 lbm ) ( 1.00 Btu / lbm - Fdeg ) ( 200 F - 40 F ) = 1335 Btu <----------------
To heat a 390 gallon tank of water from 60°F to 248°F, you would need approximately 1,251,600 BTUs. This calculation takes into account the specific heat capacity of water (1 BTU/lb°F) and the weight of water (8.34 lbs/gallon).
Heating a gallon of water by one degree Celsius requires around 8,337 BTUs (British Thermal Units) of energy. Since 1 cubic foot of natural gas produces about 1,031 BTUs, you would need roughly 8 cubic feet of natural gas to heat a gallon of water by one degree Celsius.
BTUs, or British Thermal Units, measure the amount of heat energy required to raise the temperature of one pound of water by one degree Fahrenheit. The formula to calculate BTUs is: BTUs = weight of water (in pounds) x temperature change (in degrees Fahrenheit) x 1. Alternatively, the formula can be expressed as: BTUs = (Flow rate in gallons per minute x change in temperature in degrees Fahrenheit) / 500.
To determine the heating capacity of an electric hot water heater in terms of British Thermal Units (BTUs), you can use the formula: Watts x 3.41 = BTUs. Simply multiply the wattage of the heater by 3.41 to convert it to BTUs.
None. When water freezes it _releases_ energy (the heat of fusion, 333.55 kj.kg). To keep it from freezing, simply keep the energy constant. If the ambient temperature is below zero C (32 F) the rate of energy loss will depend on the temperature of the air and the thermal resistance (insulation value) of the water's container, and other factors such as wind speed. In those conditions you must replace the energy lost to prevent the water from freezing. However, the energy needed depends on the rate of loss, not on the amount of water.
To heat a 390 gallon tank of water from 60°F to 248°F, you would need approximately 1,251,600 BTUs. This calculation takes into account the specific heat capacity of water (1 BTU/lb°F) and the weight of water (8.34 lbs/gallon).
100 BTU if it's Fahrenheit
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
There are no units for the temperature. The temperature change could be 230 Celsius degrees or 170 Fahrenheit degrees (94 Celsius degrees). In fact they could be in less commonly used units: eg Reaumur.
It takes 8.33 BTUs to heat up one gallon of water by one degree Fahrenheit. The amount of energy needed to heat the water to a desired temperature will depend on the starting temperature and the desired final temperature.
That will completely depend on how much water there is.
To calculate the BTUs required to raise the temperature of 15 pounds of water, you can use the formula: BTUs = Weight of water in pounds × Temperature change in degrees Fahrenheit × 1 BTU So, the calculation would be: BTUs = 15 lbs × (130°F - 100°F) × 1 BTU = 15 lbs × 30°F = 450 BTUs.
The number of BTUs needed to heat a space to 70 degrees will depend on factors such as the size of the space, insulation levels, outdoor temperature, and efficiency of the heating system. A general estimate is around 25-30 BTUs per square foot. It is recommended to consult a heating professional for a more accurate calculation.
2250
25
To raise 1 pound of ice from 32°F to water at 32°F it requires 144 BTUs. Since you have 50 pounds of ice, you would need 50 * 144 BTUs to raise the ice to water at 32°F. To further raise the water from 32°F to 160°F, you would need an additional amount of BTUs based on the specific heat capacity of water.
About 114,000 BTU per US gallon.