Assuming you don't repeat letters:* 7 options for the first letter
* 6 options for the second letter
* 5 options for the third letter
* 4 options for the fourth letter
(Multiply all of the above together.)
The word "SMILE" consists of 5 distinct letters. The number of different arrangements of these letters can be calculated using the factorial of the number of letters, which is 5!. Therefore, the total number of arrangements is 5! = 120.
None
There are 13 letters in "the world topic". This includes 2 ts and 2 os. Therefore there are 13!/[2!*2!] = 1556755200 different arrangements.
The word "MATH" consists of 4 unique letters. The number of different arrangements of these letters can be calculated using the factorial of the number of letters, which is 4!. Therefore, the total number of arrangements is 4! = 4 × 3 × 2 × 1 = 24. Thus, there are 24 different ways to arrange the letters in the word "MATH."
There are 12 two letter arrangements of the letters in PARK.
None
120.
There are 13 letters in "the world topic". This includes 2 ts and 2 os. Therefore there are 13!/[2!*2!] = 1556755200 different arrangements.
The word "MATH" consists of 4 unique letters. The number of different arrangements of these letters can be calculated using the factorial of the number of letters, which is 4!. Therefore, the total number of arrangements is 4! = 4 × 3 × 2 × 1 = 24. Thus, there are 24 different ways to arrange the letters in the word "MATH."
There are 12 two letter arrangements of the letters in PARK.
432
That's eight letters, so: 8! = 40320 different arrangements. n! means "factorial", and the expression expands to n*(n - 1)*(n - 2) ... * 2 * 1
The word "BOX" consists of 3 distinct letters. The number of arrangements of these letters can be calculated using the factorial of the number of letters, which is 3! (3 factorial). Therefore, the total number of arrangements is 3! = 3 × 2 × 1 = 6. Thus, there are 6 possible arrangements of the letters in "BOX."
There are (1*5*4)*(3*2*1) = 120 arrangements.
720 (6 x 5 x 4 x 3 x 2)
The letters AA, bb, and cc can be combined to form different arrangements. Specifically, there are a total of 6 unique combinations, which are: AAbc, AbAc, AbcA, bAcA, bAca, and cAAb. Since there are repeated letters, the total arrangements can be calculated using the formula for permutations of multiset: ( \frac{n!}{n_1! \cdot n_2! \cdot n_3!} ), where ( n ) is the total number of letters and ( n_1, n_2, n_3 ) are the counts of each unique letter. In this case, it results in ( \frac{6!}{2! \cdot 2! \cdot 2!} = 90 ) unique arrangements.
There is no direct anagram. The largest of the 18 English words using those letters are "timing" and "minty".