720 (6 x 5 x 4 x 3 x 2)
240
There are 5*4*3 = 60 permutations.
There are 5 ways to choose the first letter, 4 ways to pick the second letter, 3 ways to select the third, 2 options for the fourth letter leaving just one way to pick the final letter. The number of arrangements are thus 5 x 4 x 3 x 2 x 1 = 120
nkhnlk453
At least three.
The anagram is "absent."
240
Algorithm is the only nine letter word.
120
That's eight letters, so: 8! = 40320 different arrangements. n! means "factorial", and the expression expands to n*(n - 1)*(n - 2) ... * 2 * 1
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
8 different 4-letter words can be formed from the letters of the word "Nation".
There are 7!/(3!*2!) = 420 ways.7! for the seven letters in "success", butthere are 3 s which are indistinguishable, so divide by 3!there are 2 c which are indistinguishable, so divide by 2!
Words that can be made with the letters in 'gazebo' are:aageagobagbebegboabogegogabgazegogob
The word "IMAGINARY" has 9 letters, including 4 vowels (I, A, I, A) and 5 consonants (M, G, N, R, Y). To find the number of arrangements where the vowels do not come together, first calculate the total arrangements of the letters (considering the repeated vowels) and then subtract the arrangements where the vowels are together, treating them as a single unit. After performing these calculations, the total number of arrangements where the vowels never come together is found to be 2880.
There are a total of 15 letters in "season greetings." To calculate the number of words that can be formed, we first need to determine the number of unique arrangements of these letters. This can be calculated using the formula for permutations of a multiset, which is 15! / (2! * 2! * 2! * 2! * 2! * 2! * 1!). This results in 1,816,214,400 unique arrangements. However, not all of these arrangements will form valid English words, as many will be nonsensical combinations of letters.
To determine how many words can be formed with the letters "h" and "m" together, treat "hm" as a single unit or letter. For example, if you have the letters "a, b, c, h, m", you would consider "hm" as one unit, resulting in the units: "a, b, c, hm". The total arrangements would then be calculated based on the number of unique units. The exact number of arrangements depends on the total number of letters available and their uniqueness.