Q: How many different arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once?

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The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.

The letters T and L are formed as asked.l and t from fiona1234

Answer 9!/3!2!=30240 Note there are three a's and two p's and a total of 9 letters in apparatus. So there are 9 choices for the first letter, and 8 for the next, then 7 for the third etc. The we divide by 3! and 2! to avoid overcounting. The answer is 9!/3!2! The numerator can be written as 9! which is pronounced 9 factorial. Then we divide that by 3! times 2! In general if you have have n letters, there are n! words you can make, However, if some of the letters are repeated you must divide to avoid overcounting. If letter a is repeated r1 times, b r2 times, c r3 times.. etc, Then the number of words is n!/r1!r2!r3!

X and T because the they can still make the T shape and still be perpendicular

In a set, as it is usually defined, elements can't be repeated. "Mathematics" has 8 distinct letters, so your set would have 8 letters. The number of possible subsets (this includes the empty set, and the set itself) is two to the power 8.

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240

Algorithm is the only nine letter word.

120

The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.

720 (6 x 5 x 4 x 3 x 2)

There are 7!/(3!*2!) = 420 ways.7! for the seven letters in "success", butthere are 3 s which are indistinguishable, so divide by 3!there are 2 c which are indistinguishable, so divide by 2!

8 different 4-letter words can be formed from the letters of the word "Nation".

Words that can be made with the letters in 'gazebo' are:aageagobagbebegboabogegogabgazegogob

The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.

The answer is 5!, 5 factorial. This equals 5 X 4 X 3 X 2 X 1, which is 120.

6*5*4*3*2*1=720

Molecules are formed by different arrangements of atoms. Example: one molecule of water is formed by 2 atoms of hydrogen and one atom of oxygen. (H2O). This is called the formula of a molecule.