That would be all the numbers that end with 0 or 5. So:* For the first digit, you have 9 options (digits 0-9).
* For the second digit, you have 10 options.
* For the third digit, you have 10 options.
* For the fourth digit, you have 2 options (the digits 0 or 5).
You can multiply all those together.
1800 of them.
There are an infinite number of multiples of 5
lcm(2, 3, 5) = 30 → 2 digit common multiples are 30, 60, 90.
The integers divisible by those 5 numbers are exactly the multiples of 1008. The largest multiple of 1008 which is still a four-digit number is 9*1008 = 9072.
There are 7200 such numbers.
If the digits can be repeated, then there are (5 x 5 x 5 x 5) = 625 different four-digit numbers.If the digits can't be repeated, then there are (5 x 4 x 3 x 2) = 120 different four-digit numbers.
99
-4
1
There are 720 of them.
Multiples of 10 between 1000 and 9990 Any four-digit number ending in zero.
1000, 1005, 1110, 1115 and just keep adding five until you get to 9995.
Multiples of 30 from 120 to 990
There are an infinite number of multiples of 5
lcm(2, 3, 5) = 30 → 2 digit common multiples are 30, 60, 90.
5*5*4*4 = 400
There are 2000 4-digit numbers that are multiples of 5, so, instead of listing them all, it is equally valid to say: Any4-digit number whose final digit is either a 5 or a 0 is a multiple of 5. Get Right? :P
NO. All multiples of 5 have a final digit of 0 or 5. Therefore 1001 with its final digit of 1 is NOT a multiple of 5.